![The equation of state a van der Waal gas can be expressed as Z=1+dfrac{B}{V_m}+dfrac{C}{V^2_m}+..... If the van der Waal constants a and b are 1.344 litre^2 atm/mol^2 and 0.03 litre mol^{-1}, respectively, The equation of state a van der Waal gas can be expressed as Z=1+dfrac{B}{V_m}+dfrac{C}{V^2_m}+..... If the van der Waal constants a and b are 1.344 litre^2 atm/mol^2 and 0.03 litre mol^{-1}, respectively,](https://haygot.s3.amazonaws.com/questions/1486404_1680513_ans_ee8a1beb14b94a4c9222081de359e440.png)
The equation of state a van der Waal gas can be expressed as Z=1+dfrac{B}{V_m}+dfrac{C}{V^2_m}+..... If the van der Waal constants a and b are 1.344 litre^2 atm/mol^2 and 0.03 litre mol^{-1}, respectively,
How real gases are different from ideal gases? Derive van der Waal's equation by pressure and volume modifications. - Sarthaks eConnect | Largest Online Education Community
![SOLVED: P3E.4 Consider gases described by the following three equations of state: RT perfect: p = V RT van der Waals: p = Vn-b VZ RTe-"RTVm (c) Dieterici: p = Vm b SOLVED: P3E.4 Consider gases described by the following three equations of state: RT perfect: p = V RT van der Waals: p = Vn-b VZ RTe-"RTVm (c) Dieterici: p = Vm b](https://cdn.numerade.com/ask_images/b491eee1ef9c425bbaf79168b2696bae.jpg)